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+--- Thread: [b]"How to use Selenium to find the last li in ul?"[/b] or [b]"What's the best way to find the last li in ul using (/thread-b-how-to-use-selenium-to-find-the-last-li-in-ul-b-%0A%0Aor-%0A%0A-b-what-s-the-best-way-to-find-the-last-li-in-ul-using)
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[b]"How to use Selenium to find the last li in ul?"[/b] or [b]"What's the best way to find the last li in ul using - MaskedRogue77 - 15-12-2024
Hey everyone!
Struggling a bit here—trying to selenium find last li in ul but not getting it right. Tried a few things like `driver.find_elements_by_xpath("//ul/li")[-1]`, but it feels kinda hacky.
Is there a cleaner way? Maybe with CSS selectors or something more reliable?
Also, what if the list updates dynamically? Would love some tips or your go-to methods for this.
Thanks in advance! 🙌
(PS: If you’ve got a snippet, even better—my brain’s fried from trial and error lol.)
“” - FirewallStorm77 - 11-02-2025
Hey! For selenium find last li in ul, you could try using CSS with `:last-child`. Like this:
`driver.find_element_by_css_selector("ul li:last-child")`
Way cleaner than XPath, imo.
If the list updates dynamically, maybe add a WebDriverWait to ensure the element is there before grabbing it.
“” - deepTrekX88 - 11-02-2025
XPath can be messy, but you could also do:
`//ul/li[last()]`
That’s the proper XPath way to get the last li.
For dynamic lists, wrap it in a wait like `WebDriverWait(driver, 10).until(...)` to avoid flakiness.
“” - stealthXchange88 - 10-03-2025
Dude, I feel you. Selenium find last li in ul is one of those things that seems simple but trips you up.
Try this:
```python
last_li = driver.execute_script("return document.querySelector('ul li:last-child')")
```
JS might be more reliable if the DOM’s being funky.
“” - PhantomCircuit - 13-03-2025
CSS selectors are def cleaner for this.
`ul > li:last-of-type`
Works like a charm.
For dynamic content, maybe throw in a `presence_of_element_located` wait.
“” - MaskedRogue77 - 14-03-2025
You could also use `ul li:nth-last-child(1)`—same as `:last-child` but feels fancier lol.
For dynamic stuff, explicit waits are your best friend.
---
Hey, thanks everyone! The `:last-child` CSS selector worked perfectly.
One follow-up though—what if the `ul` has nested lists? Would `ul > li:last-child` still grab the right one, or do I need to adjust?
Also, big shoutout for the WebDriverWait tips—totally saved me from race conditions. 🙏
“” - DeepWebWalker - 19-03-2025
If you’re stuck on selenium find last li in ul, check out the `:-soup-selector` in BeautifulSoup if you’re parsing static HTML.
But for Selenium, stick with `:last-child` or XPath `last()`.
Also, Chrome DevTools can help verify your selectors before coding.
“” - ZeroVisibilityX - 19-03-2025
For dynamic lists, you might wanna poll for changes. Something like:
```python
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
wait = WebDriverWait(driver, 10)
last_li = wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, "ul li:last-child")))
```
Works like a charm for me.
“” - dataDash99 - 26-03-2025
Honestly, your XPath hack isn’t *that* bad. But yeah, `:last-child` is cleaner.
If the list’s super dynamic, maybe even check for `li` count first with `len(driver.find_elements_by_css_selector("ul li"))` to be safe.