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+--- Thread: [b]"How to Python3 get response code from urllib? Best way to check HTTP status?"[/b] or [b]"Python3 get response (/thread-b-how-to-python3-get-response-code-from-urllib-best-way-to-check-http-status-b-%0A%0Aor-%0A%0A-b-python3-get-response)
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[b]"How to Python3 get response code from urllib? Best way to check HTTP status?"[/b] or [b]"Python3 get response - fastLurkerX - 06-09-2024
Python3 get response code from urllib – am I missing something?
Hey folks,
Trying to python3 get response code from urllib but keep getting weird errors or nothing at all. Like, I just wanna check if a URL is alive, ya know?
Using `urllib.request.urlopen()` but the status code feels hidden. Do I really need to dig into `getcode()` or catch exceptions just for this?
```python
import urllib.request
try:
with urllib.request.urlopen('https://example.com') as response:
print(response.getcode()) # finally found it!
except urllib.error.URLError as e:
print("RIP, site's down:", e)
```
Is this the simplest way or am I overcomplicating it?
Also, why doesn’t it just *give* me the code upfront? Feels like extra steps.
Thx in advance!
“” - TorDrifter99 - 16-12-2024
Yeah, urllib can be a pain for python3 get response code from urllib stuff. Your code’s actually fine, but if you want something simpler, try the `requests` lib.
```python
import requests
r = requests.get('https://example.com')
print(r.status_code)
```
Way cleaner, no nesting. Plus, `requests` handles redirects and timeouts better. Downside? It’s an extra dependency.
Also, urllib hides the code cuz it’s low-level—meant for more control, not convenience.
“” - FirewallNomad99 - 03-01-2025
urllib’s design is just... old school. For python3 get response code from urllib, you’re stuck with `getcode()` or digging into exceptions. Annoying, but that’s how it is.
If you’re just checking URLs, maybe use `curl` in a subprocess?
```python
import subprocess
result = subprocess.run(['curl', '-s', '-o', '/dev/null', '-w', '%{http_code}', 'https://example.com'], capture_output=True, text=True)
print(result.stdout)
```
Overkill? Maybe. Works? Absolutely.
“” - SecureHorizonX - 09-02-2025
Honestly, your solution’s already the simplest for python3 get response code from urllib without adding libs.
But hey, if you’re doing this a lot, wrap it in a function:
```python
def get_status(url):
try:
with urllib.request.urlopen(url) as resp:
return resp.getcode()
except urllib.error.URLError as e:
return f"Error: {e}"
```
Now you can reuse it and pretend urllib isn’t clunky.
“” - TorVoyager99 - 28-02-2025
urllib’s like that one friend who makes everything complicated. For python3 get response code from urllib, yeah, `getcode()` is the way.
But if you’re open to alternatives, `httpx` is modern and async-friendly:
```python
import httpx
response = httpx.get('https://example.com')
print(response.status_code)
```
Bonus: it’s faster for bulk checks. Just sayin’.
“” - vpnStorm99 - 15-03-2025
Why’s urllib so extra? For python3 get response code from urllib, you’re not missing much—it’s just verbose.
Pro tip: if you’re on Linux, `httpie` in terminal is golden for quick checks:
```bash
http --headers GET https://example.com | grep HTTP
```
No Python, no problem.
“” - fastLurkerX - 28-03-2025
Wow, thanks y’all! Didn’t expect so many options. Tried `requests` and it’s *so* much easier—why didn’t I switch sooner?
Still weird that python3 get response code from urllib requires so much boilerplate. Might just stick with `requests` unless I’m forced to use stdlib.
Quick Q: anyone know if `httpx` plays nice with proxies? Might need that next.
“” - VPNGenius - 31-03-2025
Your code’s solid for python3 get response code from urllib. The exception handling’s necessary cuz... well, the internet’s unreliable.
If you hate typing, steal this one-liner:
```python
print(urllib.request.urlopen('https://example.com').getcode()) if True else None
```
(Just kidding. Don’t do that. Keep the try/except.)
“” - maskedDash99 - 04-04-2025
urllib’s quirks are why everyone uses `requests` for python3 get response code from urllib. But if you’re stuck with stdlib, your approach is correct.
For debugging, add `print(dir(response))`—you’ll see `getcode()` isn’t *that* hidden. Just not obvious.