Hey! Yeah, you can totally handle 404 errors in Python without crashing your script. The easiest way is to use a try-except block with `requests.get()`.
Here's a quick snippet:
```python
import requests
urls = ["http://example.com", "http://nonexistent.com"]
for url in urls:
try:
response = requests.get(url)
response.raise_for_status()
except requests.exceptions.HTTPError:
print(f"Skipping 404 for {url}")
continue
```
This way, it just skips the bad links and keeps going. Hope this helps!
Here's a quick snippet:
```python
import requests
urls = ["http://example.com", "http://nonexistent.com"]
for url in urls:
try:
response = requests.get(url)
response.raise_for_status()
except requests.exceptions.HTTPError:
print(f"Skipping 404 for {url}")
continue
```
This way, it just skips the bad links and keeps going. Hope this helps!