[b]"How to omit fields when using Python JSONDecoder?"[/b] or [b]"Python JSONDecoder omit fields - is there a clea

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Python JSONDecoder omit fields - is there a clean way to skip certain fields during decoding?

Hey folks,

I'm working with some messy JSON data and only need a few fields. Parsing everything feels wasteful, and I’m wondering if there's a way to make *python jsondecoder omit fields* I don’t care about.

Like, can I subclass `JSONDecoder` or use a hook to just *skip* certain keys? Or am I stuck filtering after decoding?

Found some old threads but nothing super clear. Maybe y’all have a slick solution?

Thanks!

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*(or a shorter version if you prefer):*

How to omit fields when using Python JSONDecoder?

Struggling with bloated JSON and just want to ignore certain fields.

Is there a way to make *python jsondecoder omit fields* during parsing, or do I gotta filter manually later?

Hooks? Overrides? Black magic?

Pls halp.

Messages In This Thread
[b]"How to omit fields when using Python JSONDecoder?"[/b] or [b]"Python JSONDecoder omit fields - is there a clea - by - 10-09-2024, 11:40 PM



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